y^2+3y=4

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Solution for y^2+3y=4 equation:


Simplifying
y2 + 3y = 4

Reorder the terms:
3y + y2 = 4

Solving
3y + y2 = 4

Solving for variable 'y'.

Reorder the terms:
-4 + 3y + y2 = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 3y + y2 = 0

Factor a trinomial.
(-4 + -1y)(1 + -1y) = 0

Subproblem 1

Set the factor '(-4 + -1y)' equal to zero and attempt to solve: Simplifying -4 + -1y = 0 Solving -4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1y = 0 + 4 -1y = 0 + 4 Combine like terms: 0 + 4 = 4 -1y = 4 Divide each side by '-1'. y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(1 + -1y)' equal to zero and attempt to solve: Simplifying 1 + -1y = 0 Solving 1 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1y = 0 + -1 -1y = 0 + -1 Combine like terms: 0 + -1 = -1 -1y = -1 Divide each side by '-1'. y = 1 Simplifying y = 1

Solution

y = {-4, 1}

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